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Let (7,-3) be a point on the terminal side of theta. Find the exact values of cos of theta, sec of theta and cot of theta?

1 answer

  1. r^2= 7^2 + (-3)^2 = 58
    r = √58

    since (7,-3) is in IV,
    cosØ = 3/√58
    secØ = √58/3
    cotØ = -7/3

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