A brick with a mass of 6kg is dropped vertically from a certain height.it takes 4,5 seconds for the brick to reach the ground.determine the ff.the height from which the brick is dropped and potential energy of the brick

h = 0.5g*t^2 = 4.9*4.5^2 = 99.23 m.

PE = mg*h = 6*9.8 * 99.23 = 5834 J.

Where did the 0.5 come from

To determine the height from which the brick is dropped, we can use the equation of motion:

h = (1/2)gt^2

where:
h = height (in meters)
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time taken (in seconds)

Plugging in the values into the equation:

h = (1/2)(9.8 m/s^2)(4.5 s)^2
h = (1/2)(9.8 m/s^2)(20.25 s^2)
h = 102.375 m

Therefore, the height from which the brick is dropped is approximately 102.375 meters.

To determine the potential energy of the brick, we can use the equation:

Potential Energy = mass x gravitational acceleration x height

Plugging in the values:

Potential Energy = (6 kg)(9.8 m/s^2)(102.375 m)
Potential Energy = 6 x 9.8 x 102.375
Potential Energy = 6072.15 Joules

Therefore, the potential energy of the brick is approximately 6072.15 Joules.

To determine the height from which the brick is dropped, we can use the equation:

h = (1/2) * g * t^2

Where:
h = height from which the brick is dropped
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time taken for the brick to reach the ground

Substituting the given values:

h = (1/2) * 9.8 * (4.5)^2
h = (1/2) * 9.8 * 20.25
h = 99.45 meters

Therefore, the brick was dropped from a height of 99.45 meters.

To determine the potential energy of the brick, we can use the equation:

PE = m * g * h

Where:
PE = potential energy
m = mass of the brick (6 kg)
g = acceleration due to gravity (approximately 9.8 m/s^2)
h = height from which the brick is dropped (99.45 meters)

Substituting the given values:

PE = 6 * 9.8 * 99.45
PE = 5829.72 joules

Therefore, the potential energy of the brick is 5829.72 joules.