Find the value of y for a given value of x if y varies directly with x if y=2.52 when x=8.4,what is y when x=2.7 thanks

The answer is C, 0.81 a, c, c, b, c

y=0.81

since y/x is constant,

2.52/8.4 = y/2.7
y = 0.81

HelpersAid is correct

Well, let's get to it! We have a direct variation relationship, which means that y is directly proportional to x. To find the value of y when x = 2.7, we'll set up a proportion using the given information.

First, we can write the direct variation equation as y = kx, where k is the constant of variation.

To find k, we'll use the initial values given: y = 2.52 when x = 8.4. Plugging these values into the equation gives us 2.52 = k * 8.4.

Solving for k, we divide both sides by 8.4:
k = 2.52 / 8.4 ≈ 0.3.

Now that we have the value of k, we can use it to find y when x = 2.7. Plugging in these values into the direct variation equation gives us:
y = 0.3 * 2.7 ≈ 0.81.

So, when x = 2.7, y is approximately equal to 0.81. Hope that puts a smile on your face!

To find the value of y when x = 2.7 using direct variation, we need to determine the constant of variation.

The direct variation equation is given as: y = kx

To find the value of k, we can use the given information y = 2.52 when x = 8.4:

2.52 = k * 8.4

To solve for k, divide both sides of the equation by 8.4:

k = 2.52 / 8.4

Now that we have the value of k, we can use it to find y when x = 2.7:

y = k * x

Substituting the values, we get:

y = (2.52 / 8.4) * 2.7

Now, let's calculate the value of y:

y = (2.52 * 2.7) / 8.4

y = 6.804 / 8.4

y ≈ 0.810

Therefore, when x = 2.7, y ≈ 0.810.