1.) Solve for x. 2x(x - 12) = -40

2.) Solve for x. 3x2 + 2x = 12 - 7x

3.) Simplify the expression. 8sqrt[-63]

4.) Find the absolute value of the complex number. Abs Val [7 + 24i]

5.) Simplify the expression. [4 - 7i] + [2 + 3i]

Thank you so much!! :)

#1

2x(x-12) = -40
x(x-12) + 20 = 0
x^2-12x+20 = 0
(x-2)(x-10) = 0

#2
3x^2 + 2x = 12 - 7x
3x^2 + 9x - 12 = 0
x^2+3x-4 = 0
(x+4)(x-1) = 0

#3
8√-63 = 8√63 i

#4
|7+24i| = √(7^2 + 24^2) = 25

#5
(4-7i)(2+3i) = 8 - 14i + 12i - 21i^2 = 29-2i

1.) To solve for x in the equation 2x(x - 12) = -40, we will first expand the equation:

2x(x - 12) = -40
2x^2 - 24x = -40

Next, we will rearrange the equation to bring all terms to one side, setting it equal to zero:

2x^2 - 24x + 40 = 0

This is now a quadratic equation in the form of ax^2 + bx + c = 0, where a = 2, b = -24, and c = 40. To solve for x, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Plugging in the values, we have:

x = (-(-24) ± √((-24)^2 - 4(2)(40))) / (2(2))
x = (24 ± √(576 - 320)) / 4
x = (24 ± √256) / 4
x = (24 ± 16) / 4

This gives us two possible solutions:

x1 = (24 + 16) / 4 = 40 / 4 = 10
x2 = (24 - 16) / 4 = 8 / 4 = 2

Therefore, the solutions for x are x = 10 and x = 2.

2.) To solve for x in the equation 3x^2 + 2x = 12 - 7x, we will first rearrange the equation to bring all terms to one side and set it equal to zero:

3x^2 + 2x + 7x - 12 = 0
3x^2 + 9x - 12 = 0

Next, we can try factoring the quadratic equation. We look for two numbers that multiply to give -36 (the product of the coefficients of x^2 and the constant term) and add up to 9 (the coefficient of x). In this case, the numbers are 12 and -3:

3x^2 + 12x - 3x - 12 = 0
(3x + 12)(x - 1) = 0

Setting each factor equal to zero and solving for x, we have:

3x + 12 = 0 -> 3x = -12 -> x = -4
x - 1 = 0 -> x = 1

Therefore, the solutions for x are x = -4 and x = 1.

3.) To simplify the expression 8sqrt[-63], we can first factor -63 into its prime factorization. The prime factorization of 63 is 3 * 3 * 7, so we can write:

8sqrt[-63] = 8sqrt[(-1)(3)(3)(7)]

Next, we can rewrite the square root of a product as the product of the square roots:

8sqrt[(-1)(3)(3)(7)] = 8sqrt[-1] * sqrt[3] * sqrt[3] * sqrt[7]

Since the square root of -1 is denoted as "i" (the imaginary unit), we have:

8sqrt[-1] * sqrt[3] * sqrt[3] * sqrt[7] = 8i * √3 * √3 * √7

Simplifying further:

8i * √3 * √3 * √7 = 8i * 3 * √7

Finally, multiplying the terms, we get:

8i * 3 * √7 = 24i√7

Therefore, the simplified expression is 24i√7.

4.) To find the absolute value of the complex number 7 + 24i, we can use the formula for finding the modulus of a complex number:

|a + bi| = √(a^2 + b^2)

Plugging in the values, we have:

|7 + 24i| = √(7^2 + 24^2)
= √(49 + 576)
= √625
= 25

Therefore, the absolute value of the complex number 7 + 24i is 25.

5.) To simplify the expression [4 - 7i] + [2 + 3i], we will combine like terms by adding the real parts and the imaginary parts separately.

Real parts: 4 + 2 = 6
Imaginary parts: -7i + 3i = -4i

Therefore, the simplified expression is 6 - 4i.