A dragster and driver together have mass 900.7 kg.

The dragster, starting from rest, attains a speed of 25.7 m/s in 0.54 s.

1. Find the average acceleration of the dragster during this time interval.
Answer in units of m/s^2.

2. What is the size of the average force on the dragster during this time interval?
Answer in units of N

3. Assume: The driver has a mass of 75 kg. What horizontal force does the seat exert on the driver?
Answer in units of N.
Answer in units of N

1. a=(V-Vo)/t = (25.7-0)/0.54=47.6 m/s^2

2. F = m*a = 900.7 * 47.6 = 42,867 N.

1. Well, if you really want to know the average acceleration of the dragster, here's a formula for you: average acceleration = (final velocity - initial velocity) / time taken. Plugging in the given values, we get (25.7 m/s - 0 m/s) / 0.54 s ≈ 47.59 m/s². So the average acceleration of the dragster during this time interval is about 47.59 m/s².

2. To find the size of the average force on the dragster, we can use Newton's second law, which states that force = mass × acceleration. Plugging in the values, we get force = 900.7 kg × 47.59 m/s² ≈ 42,844.51 N. So the size of the average force on the dragster during this time interval is approximately 42,844.51 N.

3. Since we now know the mass of the driver is 75 kg, we can use the same formula from the previous question to find the horizontal force exerted by the seat on the driver. Plugging in the values, we get force = 75 kg × 47.59 m/s² ≈ 3,569.25 N. So the horizontal force exerted by the seat on the driver is about 3,569.25 N.

To solve these questions, we'll use the following equations:

1. Average acceleration (a) = (final velocity - initial velocity) / time interval
2. Average force (F) = mass x acceleration
3. Horizontal force exerted on the driver = mass of the driver x acceleration

Given:
Mass of dragster and driver (m) = 900.7 kg
Final velocity (v_f) = 25.7 m/s
Time interval (t) = 0.54 s
Mass of driver (m_driver) = 75 kg

Step 1: Calculate the average acceleration.
Using the equation: Average acceleration (a) = (v_f - v_i) / t

Initial velocity (v_i) is 0 m/s since the dragster starts from rest.
Therefore, applying the formula, we get:
Average acceleration (a) = (25.7 m/s - 0 m/s) / 0.54 s

Calculating this value, we find:
Average acceleration (a) = 47.59 m/s^2 (rounded to two decimal places)

Step 2: Calculate the average force.
Using the equation: Average force (F) = mass x acceleration

Average force (F) = 900.7 kg x 47.59 m/s^2

Calculating this value, we find:
Average force (F) = 42,872.19 N (rounded to two decimal places)

Step 3: Calculate the horizontal force exerted on the driver.
Using the equation: Horizontal force exerted on the driver = mass of the driver x acceleration

Horizontal force exerted on the driver = 75 kg x 47.59 m/s^2

Calculating this value, we find:
Horizontal force exerted on the driver = 3,569.25 N (rounded to two decimal places)

Therefore, the answers to the questions are:
1. The average acceleration of the dragster during this time interval is 47.59 m/s^2.
2. The size of the average force on the dragster during this time interval is 42,872.19 N.
3. The horizontal force exerted on the driver by the seat is 3,569.25 N.

To find the average acceleration of the dragster during the time interval, we can use the equation:

average acceleration = change in velocity / time interval

The change in velocity is the final velocity minus the initial velocity. In this case, the initial velocity is 0 m/s since the dragster starts from rest, and the final velocity is 25.7 m/s. The time interval is given as 0.54 s.

So, average acceleration = (25.7 m/s - 0 m/s) / 0.54 s

Simplifying this calculation gives us the answer to the first question:

average acceleration = 47.59 m/s²

To find the size of the average force on the dragster during this time interval, we can use Newton's second law of motion:

force = mass × acceleration

The mass of the dragster and driver together is given as 900.7 kg, and we already calculated the average acceleration in the previous step.

So, average force = 900.7 kg × 47.59 m/s²

Calculating this value gives us the answer to the second question:

average force = 42,919.9 N

For the third question, we are asked to find the horizontal force exerted by the seat on the driver. Since there are no external horizontal forces acting on the driver, the force exerted by the seat must be equal in magnitude and opposite in direction to the force exerted by the driver on the seat.

Therefore, the horizontal force exerted by the seat on the driver is also 42,919.9 N.