The density of gold is 19.31g/cm3 and the density of platinum is 21.43 g/cm3. If equal masses of gold and platinum are transferred to equal volumes of water in separate graduated cylinders which graduated cylinder would have greatest volume change
Pick any convenient mass, say 100 g, then
mass = volume x density
Substitute and see which has the larger voluem.
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Well, if equal masses of gold and platinum are transferred to equal volumes of water, the graduated cylinder with gold will have the greatest volume change. After all, gold is denser than platinum, so it takes up less space for an equal mass. In other words, gold packs a denser punch and will make the water in the cylinder rise higher. It's like the gold saying, "I might be heavy, but I still make a big splash!"
To determine which graduated cylinder would have the greatest volume change when equal masses of gold and platinum are transferred to water, we need to compare their densities with the density of water, which is approximately 1g/cm³.
The volume change can be calculated using the formula:
Volume change = Mass / Density
Let's calculate the volume change for gold and platinum separately:
For gold:
Density of gold = 19.31g/cm³
Mass of gold = equal mass (let's assume it is 1 gram for simplicity)
Volume change for gold = Mass / Density
= 1g / 19.31g/cm³
≈ 0.052 cm³
For platinum:
Density of platinum = 21.43g/cm³
Mass of platinum = equal mass (1 gram)
Volume change for platinum = Mass / Density
= 1g / 21.43g/cm³
≈ 0.047 cm³
Comparing the volume changes, we can see that the volume change for gold is approximately 0.052 cm³, while the volume change for platinum is approximately 0.047 cm³. Therefore, the graduated cylinder containing gold would have the greatest volume change.
So, the graduated cylinder with the gold would experience a greater increase in volume compared to the graduated cylinder with platinum when the same mass of each metal is transferred to equal volumes of water.