A truck is pulling a car.
FT is the magnitude of the force that the truck exerts on the car
FC is the magnitude of the force that the car exerts on the truck
Consider the following scenarios independently.
1)The truck is driving with a constant velocity, but as it turns out, the driver of the car left the emergency brake on.
A)FT > FC
B)FT < FC
C)FT = FC > 0
D)FT = FC = 0
2)The truck is speeding up on a horizontal surface.
A)FT > FC
B)FT < FC
C)FT = FC > 0
D)FT = FC = 0
3)The truck is speeding up while driving up a mountain, neglecting friction.
A)FT > FC
B)FT < FC
C)FT = FC > 0
D)FT = FC = 0
c
c
c
Every answer is "C"
Newton's law - for every force there is an equal but opposite reaction force
1) D) FT = FC = 0 - Well, it seems like the truck and the car are having a break from exerting any force on each other. They're just hanging out together with no force to show for it.
2) A) FT > FC - Oh boy, the truck is really working hard to speed up! It's exerting a greater force on the car than the car is on the truck. Let's hope the car doesn't feel too left behind!
3) B) FT < FC - Hey there, Mr. Truck! Driving up a mountain is tough work, and the truck is feeling the pressure. The car is exerting a greater force on the truck, trying its best to help out. It's like having a friend push you up a hill when you're out of breath!
To solve these scenarios, we need to understand Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. In this case, the action is the force exerted by the truck on the car, and the reaction is the force exerted by the car on the truck.
1) When the truck is driving with a constant velocity, it means that there is no net force acting on the truck-car system. Since the driver of the car left the emergency brake on, there is a force of friction opposing the motion of the car. According to Newton's third law, the truck exerts an equal and opposite force on the car. Therefore, FT > FC. The correct answer is A) FT > FC.
2) When the truck is speeding up on a horizontal surface, there is an acceleration present in the truck-car system. To accelerate, the truck exerts a greater forward force on the car. According to Newton's third law, the car exerts an equal and opposite force on the truck. Therefore, FT > FC. The correct answer is A) FT > FC.
3) When the truck is speeding up while driving up a mountain, neglecting friction, we need to consider the forces acting on the truck-car system. The truck is exerting a forward force to accelerate up the slope, and gravity is pulling the truck and the car downhill. Since the truck is accelerating, the forward force exerted by the truck must be greater than the force of gravity acting on the truck and the car combined. According to Newton's third law, the car exerts an equal and opposite force on the truck. Therefore, FT > FC. The correct answer is A) FT > FC.
In all three scenarios, the correct answer is A) FT > FC.
1.a
2.b