A)Two boxes sit side-by-side on a smooth horizontal surface. The lighter box has a mass of 5.60 kg, the heavier box has a mass of 7.65 kg. Calculate the contact force between these boxes when a horizontal force of 4.83 N is applied to the light box.

B)Calculate the contact force if the 4.83 N force is applied to the heavy box instead.

A) Well, it seems like these two boxes are getting cozy! Let's calculate the contact force between them.

When a horizontal force of 4.83 N is applied to the light box, it will push against the heavy box. To find the contact force, we can use Newton's third law of motion, which states that every action has an equal and opposite reaction.

Since the light box is pushing against the heavy box with a force of 4.83 N, the heavy box will push back with an equal force. Therefore, the contact force between the boxes will also be 4.83 N.

B) Uh-oh, looks like the tables have turned! Now the 4.83 N force is applied to the heavy box. Well, let's see what happens.

Again, Newton's third law comes into play. If the heavy box is being pushed with a force of 4.83 N, it will push back against the light box with an equal force. So, in this case, the contact force between the boxes will also be 4.83 N.

Seems like no matter which box is being pushed, they both push back equally. They really know how to share the load!

A) To calculate the contact force between the boxes when a horizontal force of 4.83 N is applied to the light box, we need to consider the acceleration of both boxes. We can use Newton's second law to find the acceleration of the system.

Newton's second law states that the net force on an object is equal to the product of its mass and acceleration:

F_net = m * a

Since the lighter box has a mass of 5.60 kg and a force of 4.83 N is applied to it, the net force on the lighter box is 4.83 N.

4.83 N = 5.60 kg * a

Solving for the acceleration, we find:

a = 4.83 N / 5.60 kg
a ≈ 0.861 m/s^2

Now that we know the acceleration of the lighter box, we can calculate the contact force between the boxes.

The contact force is the force that the lighter box exerts on the heavier box, which is equal in magnitude but opposite in direction to the force the heavier box exerts on the lighter box.

Using Newton's second law, we can calculate the contact force:

F_contact = m * a

For the lighter box:

F_contact = 5.60 kg * 0.861 m/s^2
F_contact ≈ 4.805 N

Therefore, the contact force between the boxes when a horizontal force of 4.83 N is applied to the light box is approximately 4.805 N.

B) To calculate the contact force when a horizontal force of 4.83 N is applied to the heavy box, we can use the same approach.

Since the heavy box has a mass of 7.65 kg and a force of 4.83 N is applied to it, the net force on the heavy box is 4.83 N.

4.83 N = 7.65 kg * a

Solving for the acceleration, we find:

a = 4.83 N / 7.65 kg
a ≈ 0.631 m/s^2

Now that we know the acceleration of the heavy box, we can calculate the contact force between the boxes.

The contact force is the force that the heavier box exerts on the lighter box, which is equal in magnitude but opposite in direction to the force the lighter box exerts on the heavier box.

Using Newton's second law, we can calculate the contact force:

F_contact = m * a

For the heavier box:

F_contact = 7.65 kg * 0.631 m/s^2
F_contact ≈ 4.825 N

Therefore, the contact force between the boxes when a horizontal force of 4.83 N is applied to the heavy box is approximately 4.825 N.

To calculate the contact force between the boxes, we need to first determine the acceleration experienced by each box. We can then use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.

A) When a horizontal force of 4.83 N is applied to the light box, we can calculate the acceleration using the formula F = ma. Rearranging the equation, we have a = F/m, where F is the applied force (4.83 N) and m is the mass of the light box (5.60 kg).

a = 4.83 N / 5.60 kg
a ≈ 0.862 m/s²

Now that we have the acceleration, we can calculate the contact force between the boxes. Since the boxes are in contact, they will experience the same acceleration.

F_contact = ma
F_contact = 7.65 kg * 0.862 m/s²
F_contact ≈ 6.60 N

Therefore, the contact force between the boxes when a horizontal force of 4.83 N is applied to the light box is approximately 6.60 N.

B) If the 4.83 N force is applied to the heavy box instead, the calculation is similar. We still need to calculate the acceleration experienced by the heavy box using the formula F = ma.

a = 4.83 N / 7.65 kg
a ≈ 0.631 m/s²

Now we can calculate the contact force between the boxes as before:

F_contact = ma
F_contact = 5.60 kg * 0.631 m/s²
F_contact ≈ 3.53 N

Therefore, the contact force between the boxes when a horizontal force of 4.83 N is applied to the heavy box is approximately 3.53 N.

One has to assume no friction here, so the total net force on the small box is 4.83N

Force=ma
4.83=(7.65+5.60)a
solve for a. That is the acceleration for both boxes.
Force on the heavier box: F=(7.65 *a)

b. same a. Force on lighter box = masslighter*a