The number has two digits. Both of the digits are even.the digit in the tens place is greater that the digit in the unit (or ones) place.the units (or ones digit) is not in the three times table. The tens digit is not double the ones digit. The sum of the two digits is a multiple of five.
To find a number that satisfies all these conditions, we need to analyze each condition individually and find a number that meets all of them.
Condition 1: The number has two digits. Both of the digits are even.
We can start by listing all the even digits: 0, 2, 4, 6, 8. Since both digits are even, we can combine them in all possible ways to find the two-digit numbers that satisfy this condition: 02, 04, 06, 08, 20, 22, 24, 26, 28, 40, 42, 44, 46, 48, 60, 62, 64, 66, 68, 80, 82, 84, 86, 88.
Condition 2: The digit in the tens place is greater than the digit in the units place.
From the list of numbers we generated, we can eliminate any numbers where the tens digit is smaller than or equal to the units digit. This leaves us with the following numbers: 24, 26, 28, 42, 44, 46, 48, 62, 64, 66, 68, 82, 84, 86, 88.
Condition 3: The units digit is not in the three times table.
The multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, etc. From the remaining numbers, we can eliminate any numbers where the units digit is in the three times table. This leaves us with the following numbers: 24, 28, 44, 46, 62, 64, 68, 82, 88.
Condition 4: The tens digit is not double the units digit.
From the remaining numbers, we can eliminate any numbers where the tens digit is double the units digit. This leaves us with the following numbers: 24, 44, 46, 62, 64, 68, 82, 88.
Condition 5: The sum of the two digits is a multiple of five.
From the remaining numbers, we can find the numbers where the sum of the two digits is a multiple of five. The numbers that satisfy this condition are: 24, 44, 62, 88.
Therefore, the numbers that meet all the given conditions are: 24, 44, 62, and 88.
I am confused. 😕
The answer is 64
the number is tu
t > u
u is in {2,4,8}
t ≠2u
t+u = is in {5,10,15}
we know that t+u=10 because each is odd
u≠8 because 9+2=10 and t>u
u≠4 because 4+6=10 but t≠3k
Looks like the number is 82