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 physics
a 65kg person dives into the water from the 10m platform. she comes to a stop 2m below the surface of the water. what net force did the water exert on the swimmer?
so for the net force i got 2548N
i know: vf^2=vi^2 + 2ad
vf^2 = 0 + 2(9.8)(10)
vf^2 = 196
vf=14m/s therefore to get the force normal i first got the acceleration of the force normal by:
vf^2 = vi^2 + 2ad
since vf at 2m into the water is 0
0 = 196 + (2)(a)(2)
196 = 4a
49 = a
for the force normal i did the n = m*a
normal = 65*49
normal = 3185
force gravity = m*g
forge gravity = 65 * 9.8
force gravity = 637
force gravity + force normal = net force
net force = 637 + (3185)
net force = 2548N
but i don't trust my answer, someone please help me understand what i did wrong if i did anything wrong
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