Juan ate 1/3 of the jellybeans. Maria then ate 3/4 of the remaining jelly beans, which left 10 jelly beans. How many jelly beans were there to begin with?

original number ---- x

Juan ate (1/3)x , leaving (2/3)x

Maria ate 3/4 of that , leaving (1/4)((2/3)x = (1/6)x

(1/6)x = 10
x = 60
There were 60 j-beans

check:
Juan ate 1/3 of the 60 or he ate 20 , leaving 40
Maria ate (3/4) of the 40 , or 30, which would leave 10

Let's assume the number of jellybeans to begin with as "x."

Juan ate 1/3 of the jellybeans, which means 1 - 1/3 = 2/3 jellybeans were left.
Maria ate 3/4 of the remaining jellybeans, which means 2/3 * (1 - 3/4) = 2/3 * 1/4 = 1/6 of the jellybeans were left.
According to the question, 1/6 of the jellybeans were left, and that equals 10 jellybeans.

To find the starting number of jellybeans (x), we can set up the equation:

1/6 * x = 10

To isolate "x," we can multiply both sides of the equation by 6:

6 * (1/6 * x) = 6 * 10
x = 60

Therefore, there were originally 60 jellybeans.

To solve this problem, we'll work backward starting from the information given, which is that there were 10 jelly beans left after Maria ate 3/4 of the remaining beans.

Let's represent the total number of jelly beans at the beginning as "x".

Juan ate 1/3 of the jelly beans, leaving (1 - 1/3) = 2/3 of the jelly beans remaining.

Maria then ate 3/4 of the remaining jelly beans, leaving (1 - 3/4) = 1/4 of the jelly beans remaining.

We know that 1/4 of the jelly beans remaining is equal to 10 jelly beans.

So, we can set up an equation:

(1/4) * x = 10

To solve for x, we can multiply both sides of the equation by 4:

x = 10 * 4

x = 40

Therefore, there were 40 jelly beans to begin with.