a 15g bullet is fired from a rifle. it takes 2.50 * 10^3s for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 715 m/s. assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet. (answer 4290 N)
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force = change in momentum /change in time
= .015 (715/2.5)10^3 = 4.29 *10^3 = 4290 N 👍
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answered by Damon
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