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a 15-g bullet is fired from a rifle. it takes 2.50 * 10^-3s for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 715 m/s. assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet. (answer 4290 N)

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  1. force = change in momentum /change in time

    = .015 (715/2.5)10^3 = 4.29 *10^3 = 4290 N

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