a 15-g bullet is fired from a rifle. it takes 2.50 * 10^-3s for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 715 m/s. assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet. (answer 4290 N)
Well, well, well, looks like we've got a speedy bullet here! Let me do some number crunching for you.
To find the average net force exerted on the bullet, we can start by using the equation:
Net Force = (Mass of the bullet) x (Acceleration)
We know the mass of the bullet is 15 grams, but let's convert that to kilograms to avoid any units mishaps. Grams, well, they like to cause confusion.
So, the mass of the bullet is 0.015 kilograms. Now, let's figure out the acceleration.
Acceleration = (Change in Velocity) / (Time)
The initial velocity of the bullet is 0 m/s (since it was at rest in the barrel), and the final velocity is 715 m/s. The time it took for the bullet to reach that velocity is 2.50 * 10^-3 seconds. Let's plug in the values:
Acceleration = (715 m/s - 0 m/s) / (2.50 * 10^-3 s)
Acceleration = 286,000 m/s²
Now that we have the acceleration, we can find the average net force:
Net Force = (0.015 kg) x (286,000 m/s²)
Net Force ≈ 4,290 N
And there you have it, my friend! The average net force exerted on the bullet is approximately 4,290 N. Keep that bullet flying!
To find the average net force exerted on the bullet, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a): F = m * a.
Given:
- Mass of the bullet (m) = 15 g = 0.015 kg
- Time taken for the bullet to travel the length of the barrel (t) = 2.50 * 10^-3 s
- Exit velocity of the bullet (v) = 715 m/s
First, let's calculate the acceleration of the bullet using the formula:
a = (v - u) / t
Where:
- Initial velocity of the bullet (u) = 0 m/s (assumed that the bullet starts from rest)
a = (715 m/s - 0 m/s) / (2.50 * 10^-3 s)
a = 286,000 m/s^2
Next, substitute the values of mass (m) and acceleration (a) into the formula for force:
F = m * a
F = 0.015 kg * 286,000 m/s^2
F = 4,290 N
Therefore, the average net force exerted on the bullet is 4,290 N.
To find the average net force exerted on the bullet, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a): F = m * a.
Given:
Mass of the bullet (m) = 15 g = 0.015 kg
Time taken for the bullet to travel the length of the barrel (t) = 2.50 * 10^-3 s
Exit velocity of the bullet (v) = 715 m/s
We can find the acceleration (a) using the formula:
a = (v - u) / t
Where:
u = initial velocity
v = final velocity
Since the bullet starts from rest in the barrel, the initial velocity is 0 m/s. Therefore, u = 0 m/s.
a = (715 m/s - 0 m/s) / (2.50 * 10^-3 s)
a = 286000 m/s^2
Now we can plug in the values of the mass (m) and acceleration (a) into the equation F = m * a to find the average net force exerted on the bullet:
F = (0.015 kg) * (286000 m/s^2)
F = 4290 N
Therefore, the average net force exerted on the bullet is 4290 N.
Hey bots, you sure made that look hard.
What Newton actually said for his second law was force = rate of change of momentum.
that is change in (m V) / change in time or F = dP/dt
if m is constant it is m * dV / dt or F = m A ( the simple physics 1 way but watch out for special relativity)
However I did this in one short line by using the real thing, Force =- rate of change of momentum
force = change in momentum /change in time
= .015 (715/2.5)10^3 = 4.29 *10^3 = 4290 N