The product of two consecutive even numbers os 80.Find the values of the numbers.

The question answer is x=8,10....how to get it..pls help me..

x(x+2) = 80

x^2 + 2x - 80 = 0
(x+10)(x-8)
. . .

Factorization method is

X2+2x-80=0
X2(+10x-8x)-80=0
(X2+10x)(-8x-80)=0
X(x+10)-8(x-10)=0
(X-8)(x+10)=0
(X-8)=0 or. (x+10)=0
X=8 and x=-10

What are two consecutive even numbers that when added forms 80

Well, if we break down the problem, we can see that we're looking for two consecutive even numbers whose product is 80. Let's think about it in terms of "clown math."

If we take our first number as N, then the next consecutive even number would be N + 2. Now, according to our problem, the product of these two numbers is 80. So we can set up an equation like this:

N * (N + 2) = 80

Now, let's solve this equation. But wait! Before we do that, let me tell you a joke to lighten the mood:

Why did the scarecrow win an award? Because he was outstanding in his field!

Okay, back to the problem.

N^2 + 2N = 80

Rearranging the equation, we get:

N^2 + 2N - 80 = 0

Now let’s solve this equation using the quadratic formula (or if you don't like math, just make a funny face and skip to the answer):

N = (-2 ± √(2^2 - 4 * 1 * -80)) / 2 * 1

N = (-2 ± √(4 + 320)) / 2

N = (-2 ± √324) / 2

N = (-2 ± 18) / 2

Now, we have two possible values for N:

N1= (-2 + 18) / 2 = 8

N2= (-2 -18) / 2 = -10

Since we're looking for even numbers, we can discard N2 since it’s odd. Therefore, our first number is 8.

And since the next consecutive even number is N + 2, we have:

8 + 2 = 10

So, the two numbers are 8 and 10! I hope my clown math and joke made the process more enjoyable for you!

To find the values of the consecutive even numbers whose product is 80, we can use a systematic approach:

Step 1: Let's assume the first even number as x, and since they are consecutive even numbers, the next even number would be x + 2.

Step 2: Now, we can set up the equation based on the given information: x(x + 2) = 80.

Step 3: Expanding the equation, we get x^2 + 2x = 80.

Step 4: Rearranging the equation in quadratic form, we have x^2 + 2x - 80 = 0.

Step 5: Factoring the quadratic equation, we can find the values of x: (x - 8)(x + 10) = 0.

Step 6: Setting each factor equal to zero, we have two possible solutions: x - 8 = 0 or x + 10 = 0.

For x - 8 = 0, x = 8. This means the first even number is 8.

For x + 10 = 0, x = -10. However, since we are looking for consecutive even numbers, we can disregard negative numbers.

Step 7: To find the second even number, we add 2 to the first even number: 8 + 2 = 10.

Therefore, the two consecutive even numbers whose product is 80 are 8 and 10.