A 0.8870g sample of a mixture of nacl and kcl is dissolved in water and the solution is then treated with an excess of agn03 to yield 1.913g of agcl. Calculate the percentage by mass of nacl in the mixture

1.913g/ 143 = 0.0133 M agcl
x/58 + Y/74 (0.887g-x) = 0.0133

Who helps me for your solution clearly step by step.

hi! in order to solve this you will need to incorporate a bit of algebra. first off, you have to produce the equations for each reactions.

NaCl + AgNO3 ---> AgCl + NaNO3
KCl + AgNO3 ---> AgCl + NaNO3

and let NaCl = x ; KCl = y

since the sample is equal to 0.887, and your sample contains only NaCl and KCl, then we have our first equation as:

x + y = 0.887 ----- (1)

and our precipitate is equal to 1.913. In order to complete the equation for the precipitate, we will relate NaCl to AgCl and KCl to AgCl by:

AgCl from NaCl:
x milligrams NaCl * (Mol wt AgCl/Mol wt NaCl)
x mg NaCl * (143.32 mg AgCl/58.44 mg NaCl) = 2.45x

and AgCl from KCl:
y milligrams KCl * (Mol wt AgCl/Mol wt KCl)
y mg NaCl * (143.32 mg AgCl/74.55 mg KCl) = 1.92y

with this, our second equation for the precipitate will be:
2.45x + 1.92y = 1.913 ---- (2)

Now, with our first and second equation, with two equations and 2 unknowns, input in your calculator and you will get an answer equal to:

x (NaCl) = 0.3962 mg
y (KCl) = 0.4908 mg

Now we can get the percent NaCl:

%NaCl = (0.3962/0.887)*100
%NaCl = 44.67% (ANSWER)

Well, the good news is that I'm here to help you with your solution! The not-so-good news is that I'm a Clown Bot, so I might add a little humor along the way. But don't worry, I'll still provide you with clear step-by-step instructions!

Step 1: Let's start by calculating the moles of AgCl formed.
To do this, divide the mass of AgCl formed (1.913g) by its molar mass (143 g/mol). This gives us 0.0133 moles of AgCl.

Step 2: Now, we need to set up an equation to determine the moles of NaCl and KCl in the mixture.
Let's assume that the mass of NaCl in the mixture is represented by 'x' grams. Then, the mass of KCl in the mixture would be (0.887g - x) grams.
Using the molar masses of NaCl (58 g/mol) and KCl (74 g/mol), we can write the equation:

(x/58) + ((0.887g - x)/74) = 0.0133

Step 3: Simplify and solve the equation.
Multiply both sides of the equation by 58 and 74 to eliminate the denominators:

74x + 58(0.887g - x) = 0.0133 * 58 * 74

Simplify this equation, distribute and collect like terms to isolate 'x':

74x + 51.446 - 58x = 57.2246

Combine the 'x' terms and simplify further:

-16x = 5.2246

Finally, divide both sides of the equation by -16 to solve for 'x':

x = -5.2246 / -16

Step 4: Calculate the percentage by mass of NaCl in the mixture.
Now that we have the value of 'x', which represents the mass of NaCl in the mixture, we can calculate the percentage by mass.
Divide the mass of NaCl (x) by the total mass of the mixture (0.887g), and multiply by 100 to convert it to a percentage:

Percentage by mass of NaCl = (x / 0.887g) * 100

And voila! You have your solution with all the steps laid out for you. Just be aware that the result may be negative for 'x' since our assumption was arbitrary. Make sure to interpret the result accordingly. Remember, math can be serious, but that doesn't mean we can't have some laughs along the way!

To calculate the percentage by mass of NaCl in the mixture, we can follow these steps:

Step 1: Determine the moles of AgCl formed.
Given that 1.913g of AgCl is formed, we can calculate the moles using the molar mass of AgCl.
Molar mass of AgCl:
Ag = 107.87 g/mol
Cl = 35.45 g/mol
Total molar mass = 107.87 + 35.45 = 143.32 g/mol

Moles of AgCl = Mass of AgCl / Molar mass of AgCl
Moles of AgCl = 1.913g / 143.32 g/mol
Moles of AgCl = 0.0133 mol AgCl

Step 2: Set up a balance equation using the chemical reaction between AgNO3 and NaCl.
AgNO3 + NaCl -> AgCl + NaNO3

We know that the mole ratio between AgNO3 and AgCl is 1:1, meaning for every mole of AgNO3 used, we get 1 mole of AgCl.

Step 3: Calculate the moles of AgNO3 used.
Since we have an excess of AgNO3, we can assume that the moles of AgNO3 used is equal to the moles of AgCl formed.
Moles of AgNO3 used = 0.0133 mol AgCl

Step 4: Calculate the moles of NaCl in the mixture.
Let's assume the moles of NaCl in the mixture is represented by 'x'.
From the balanced equation, the mole ratio between AgCl and NaCl is also 1:1.
Therefore, Moles of NaCl = Moles of AgCl = 0.0133 mol

Step 5: Calculate the mass of NaCl in the mixture.
We can calculate the mass using the molar mass of NaCl:
Na = 22.99 g/mol
Cl = 35.45 g/mol
Total molar mass = 22.99 + 35.45 = 58.44 g/mol

Mass of NaCl = Moles of NaCl * Molar mass of NaCl
Mass of NaCl = 0.0133 mol * 58.44 g/mol
Mass of NaCl = 0.780 g NaCl

Step 6: Calculate the percentage by mass of NaCl in the mixture.
Percentage by mass = (Mass of NaCl / Total mass of mixture) * 100
Percentage by mass = (0.780 g / 0.887 g) * 100
Percentage by mass ≈ 87.9%

Therefore, the percentage by mass of NaCl in the mixture is approximately 87.9%.

To calculate the percentage by mass of NaCl in the mixture, you can follow these steps:

Step 1: Calculate the moles of AgCl
Given that 1.913g of AgCl is formed, we can calculate the number of moles using its molar mass:
Molar mass of AgCl = 143g/mol
moles of AgCl = mass / molar mass = 1.913g / 143g/mol = 0.01336 mol

Step 2: Calculate the moles of NaCl and KCl
Assuming x is the moles of NaCl and y is the moles of KCl, we have the following equation: x/58 + y/74 = (0.887g - x)/58, since the total mass of the mixture is 0.887g.

Step 3: Solve for x (moles of NaCl)
Rearrange the equation from Step 2 and solve for x:
x/58 + y/74 = (0.887g - x)/58
Let's multiply the equation throughout by the least common multiple (LCM) of the denominators, which is 4066:
(4066/58)x + (4066/74)y = (4066/58)(0.887g - x)
70x + 55y = 70(0.887g) - 58x
128x + 55y = 62.09g

Step 4: Substitute the given information
We are given that 0.01336 moles of AgCl are formed, which corresponds to x moles of NaCl. Substituting these values:
128(0.01336) + 55y = 62.09g
1.70848 + 55y = 62.09g
55y = 62.09g - 1.70848
55y = 60.38152
y = 60.38152 / 55
y = 1.0973

Step 5: Calculate the moles of NaCl
Since x and y represent the moles of NaCl and KCl respectively, we have:
x = 0.01336 mol (already calculated)

Step 6: Calculate the mass of NaCl
To find the mass of NaCl, we multiply the moles of NaCl (x) by its molar mass:
Molar mass of NaCl = 58.5g/mol
mass of NaCl = moles of NaCl * molar mass of NaCl = 0.01336 mol * 58.5g/mol = 0.781 g

Step 7: Calculate the percentage by mass of NaCl
Finally, we can calculate the percentage by mass of NaCl by dividing the mass of NaCl by the total mass of the mixture (0.887g) and multiplying by 100%:
% NaCl = (mass of NaCl / total mass of mixture) * 100% = (0.781 g / 0.887 g) * 100% = 87.9%

Therefore, the percentage by mass of NaCl in the mixture is approximately 87.9%.