0.887g sample of a mixture of nacl and kcl is dissolved in water. The solution is then treated with an excess agn03 to yield 1.1930of agn03. Calculate the percent by mass of each compound in the mixture
agcl = 143g/mol
1.1930/143 = 0.001337 m agcl
x/58g/mol + (0.8870g -x) + y/74g/mol = 0.001337
The right answer 87.7%
Who helps me step by step
Well, it looks like you're doing some calculations involving the mass and molar masses of different compounds. Let me try to help you step by step:
1. First, let's assume that the mass of NaCl in the mixture is represented by "x" grams.
2. Since the total mass of the mixture is 0.887 grams, the mass of KCl in the mixture would be (0.887 - x) grams.
3. Now, we can calculate the moles of AgCl that are formed by reacting with the AgNO3. From your calculations, it seems that you've already determined the moles of AgNO3 to be 0.001337 mol.
4. The molar mass of AgCl is 143 grams/mol, so we can now multiply the moles of AgCl by its molar mass to find the mass of AgCl formed, which would be 0.001337 x 143 = 0.191531 grams.
5. During the reaction, the AgNO3 reacts with the NaCl and KCl to form AgCl. Since the AgNO3 is in excess, that means all the NaCl and KCl react to form AgCl.
6. Now, we have the mass of AgCl formed (0.191531 grams) and the initial mass of the mixture (0.887 grams). We can set up an equation to represent the conservation of mass:
x/58g/mol + (0.887 - x)/74g/mol = 0.191531/143g/mol
Here, we're dividing the masses by their respective molar masses to get the moles of NaCl and KCl, and then comparing it to the moles of AgCl formed.
7. To solve this equation and find the value of x (the mass of NaCl), you can multiply through by the common denominator (58 x 74 x 143), which would cancel out the molar mass terms.
8. After solving for x, you can find the mass of KCl as (0.887 - x) grams.
9. Finally, you can calculate the percent by mass of each compound by dividing their individual masses by the total mass of the mixture (0.887 grams) and multiplying by 100.
I hope this helps! Good luck with your calculations!
To calculate the percent by mass of each compound in the mixture of NaCl and KCl, you can follow these steps:
1. Start by determining the number of moles of AgNO3. You have 1.1930 g of AgNO3, and its molar mass is 143 g/mol. Divide the mass by the molar mass to get the number of moles:
Moles of AgNO3 = 1.1930 g / 143 g/mol = 0.008345 moles
2. Use the balanced equation between AgNO3 and AgCl to determine the number of moles of AgCl that will be formed. The coefficient ratio between AgNO3 and AgCl is 1:1, so the number of moles of AgCl formed will also be 0.008345 moles.
3. Calculate the mass of AgCl using its molar mass, which is 143 g/mol:
Mass of AgCl = Moles of AgCl x Molar mass of AgCl
= 0.008345 moles x 143 g/mol
= 1.1930 g
4. Now, subtract the mass of AgCl (1.1930 g) from the initial mass of the mixture (0.887 g) to find the mass of NaCl and KCl combined:
Mass of NaCl + KCl = Initial mass - Mass of AgCl
= 0.887 g - 1.1930 g
= -0.306 g
The negative result indicates that there was likely an error made in the measurements or calculations.
Please double-check and confirm values or equations provided.
Assuming there is no error and the initial mass and mass of AgCl are correct, please provide further information to proceed with the calculation.