A large pipe has a diameter of 9.8×10^2cm.Water flows in the pipe at a speed of 5m s^-1.Find the volume in m^3,of water that flows out from the pipe every second,correct to 2 significant fogures.[Take pai as 3.142]

9.8x10^2 cm = 980cm = 9.8m

So, the rate of flow is

pi*4.9^2 m^2 * 5m/s = 377 m^3/s

Steve,how to get 4.9?

Ohh..i got it..divide two..thanks a lot!

To find the volume of water that flows out from the pipe every second, we need to calculate the cross-sectional area of the pipe and multiply it by the speed of the water.

Step 1: Calculate the radius of the pipe.
The diameter of the pipe is given as 9.8×10^2 cm. To find the radius, we divide the diameter by 2.
Radius = diameter / 2
Radius = (9.8×10^2 cm) / 2
Radius = 4.9×10^2 cm

Step 2: Convert the radius to meters.
Since the speed of water is given in meters per second, we need to convert the radius from centimeters to meters.
Radius (in meters) = Radius (in cm) / 100
Radius (in meters) = (4.9×10^2 cm) / 100
Radius (in meters) = 4.9×10^0 meters
Radius (in meters) = 4.9 meters

Step 3: Calculate the cross-sectional area of the pipe.
The formula for the area of a circle is A = πr^2, where π is approximately equal to 3.142 and r is the radius of the circle.
Area = π × radius^2
Area = 3.142 × (4.9 meters)^2
Area = 3.142 × 24.01 square meters
Area ≈ 75.57 square meters

Step 4: Calculate the volume of water flow.
The volume of water flow per second can be calculated by multiplying the cross-sectional area by the speed of water.
Volume = Area × speed
Volume = 75.57 square meters × 5 meters per second
Volume ≈ 377.85 cubic meters

Therefore, the volume of water that flows out from the pipe every second is approximately 377.85 cubic meters, correct to 2 significant figures.