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Complete and balance the following neutralization reactions. then, write the names of all the reactants and all the products in each chemical reaction.

A) HNO3 + Al(OH)3

= 3HNO3 + Al(OH)3 -> Al(NO3)3 + 3H2O

Reactants: Nitric acid, Aluminum hydroxide

Products: Aluminum nitrate, water

B) HF + KOH -> KF + H2O

Reactants: Hydrofluoric acid, Potassium hydroxide

Products: Potassium fluoride, water

C) H3PO3 + Ca(OH)2

= 2H3PO3 + 3Ca(OH)2 -> Ca3(PO3)2 + 2H20

Reactants: Phosphic acid, Calcium hydroxide

Products: Calcium phosphate, water

D) CH3COOH + NaOH

= CH3COOH + Na(OH)3 -> Na(CH3COO)3 + 3H2O

Reactants: Acetic acid, Sodium hydroxide

Products: Sodium acetate, water

E) H2SO4 + NaOH

= H2SO4 + Na(OH)2 -> Na(SO4)2 + 2H2O

Reactants: Sulphic acid, sodium hydroxide

Products: Sodium sulphate, water

I couldn't really figure out how to do the last few, but I managed to try. Your assistance will be longed-for.

Question ID
378796

Created
July 13, 2010 2:06am UTC

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https://questions.llc/questions/378796

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5 answers

  1. A and B are ok. The others are not right.
    For B, technically, I think HF should be called hydrogen fluoride since HF(aq) is hydrofluoric acid (that is a water soln of HF is called the acid).
    For the others, let me remind you of a rule (I think) I wrote last night.
    Rule. In balancing equations you may NOT change the subscripts. You may change ONLY the coefficients. Thus, Na(OH)2 and that kind of thing is a NO, NO. Try those again.
    For C, look at the O and H. Those atoms don't balance.

    Answer ID
    378815

    Created
    July 13, 2010 3:12am UTC

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  2. C) H3PO3 + Ca(OH)2

    = H3PO3 + 3CaOH2
    Reactants: Phosphic acid, Calcium hydroxide

    Products: Calcium phosphate, water

    Could you provide me an example of what you mean by that rule. I sort of understand, but an example would be better.

    Answer ID
    378817

    Created
    July 13, 2010 3:20am UTC

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  3. E) H2SO4 + NaOH

    = H2SO4+ 2NaOH --> 2H2O + Na2SO4

    About the last 2 in Na2SO4, It should be a coefficient right? Not a subscript.

    Reactants: Sulphic acid, sodium hydroxide

    Products: Sodium sulphate, water

    Answer ID
    378820

    Created
    July 13, 2010 3:33am UTC

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  4. If you meant phosphoric acid, it should be H3PO4. I will use that anyway as an example. The rule is that you
    1. Write the formula of the reactants and products.
    2. Then balance the equation by changing th coefficients. You may not change any subscripts AFTER the formula has been determined. WHY? Because you change the formula when you change subscripts. That is, NaOH is sodium hydroxide and if you change that to Na(OH)2 to balance the OH ions somewhere, Na(OH)2 is not sodium hydroxide any longer. In fact, there is no such thing as Na(OH)2. The ONLY way to get two more OH ions there, is to write 2NaOH. True, that makes two more Na atoms, also, but such is life. That makes it necessary to change Na somewhere in order to balance the extra Na but it always works out.
    H3PO4 + Ca(OH)2 ==> Ca3(PO4)3 + H2O
    2H3PO4 + 3Ca(OH)2 ==> Ca3(PO4)2 + 6H2O

    Note that the formula I started with in the first line are exactly the same as the balanced equation in the second line. I made everything balance without changing any subscripts. I changed only coefficients.

    For
    H2SO4 + NaOH ==> Na2SO4 + H2O
    H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
    Same thing. Note the formulas in line 1 and line 2 are the exact same thing; however, I changed coefficients to balance the equation.

    For
    CH3COOH + NaOH ==> CH3COONa + H2O
    Balanced as is.
    CH3COOH is acetic acid and all four (4) H atoms are not acidic; only the one in bold print.
    CH3COOH
    You may see this written as HC2H3O2, also, which is one way of showing that only the first H shown is acidic.

    Answer ID
    378835

    Created
    July 13, 2010 5:00am UTC

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  5. DrBob222 you have no clue how much you taught me in one day. Thank You so so much for this help of yours. How can I ever thank you.

    Answer ID
    378902

    Created
    July 13, 2010 3:09pm UTC

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