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how can we obtain the areas of the irregular polygans or irregular shapes or just any closed curve...?? if we know the perimeter
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asked by
anoynomous
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In DABC,∠Q >∠R, PA is the bisector of
∠ QPR and PM is perpendicular to BQ. Prove that ∠APM = half of ( ∠Q - ∠R )
1 answer
asked by
anoynomous
397 views