Math (Integrals)

Questions

The area A between the graph of the function:g(t) = 4 - (4/t^2) and the t-axis over the interval [1, x] is: A(x) = ∫[1, x] (4
1. 3 answers
2. asked by Ray
3. 1,121 views
Find the indefinite integral in two ways.∫(2x-1)^2 dx The first way I used was using the power rule and chain rule with
1. 2 answers
2. asked by Ray
3. 520 views
∫ (2x-1)^2 dx could have two answers:a) ((2x-1)^3)/6 + C b) 4/3x^3 - 2x^2 + x + C Now the question is, how are the two answers
1. 2 answers
2. asked by Ray
3. 539 views