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Einstein
Questions and answers by visitors named
Einstein
Questions (23)
A car is driven at a constant speed of 21 m/s (76km/h) down a road. The car's engine delivers 52 kW of power. Calculate the
5 answers
5,744 views
An experimental train has a mass of 1.70e4 kg and is powered across a level track by a jet engine that produces a thrust of
2 answers
920 views
A 20.0 kg cart is moving with a velocity of 7.30 m/s down a level hallway. A constant force of -11.0 N acts on the cart and its
3 answers
949 views
An archer puts a 0.28 kg arrow to the bow string. An average force of 200 N is exerted to draw the sting back 1.1 m. a) Assuming
2 answers
617 views
A rifle is fired in a valley with parallel vertical walls. The echo from one wall is heard 1.0s after the rifle was fired. The
4 answers
4,770 views
Carol drops a stone into a mine shaft 12.6 m deep. How soon after she drops the stone does she hear it hit the bottom of the
6 answers
966 views
One closed pipe organ has a length of 2.5 m.
The frequency of the note is 34.3 Hz. When a second pipe is played at the same time,
2 answers
1,097 views
A 65 kg dancer leaps .32 m high.
a) With what momentum does the dancer reach the ground? b) What impulse is needed to make a
5 answers
2,308 views
Rachel pulls her 13 kg suitcase at a constant speed by pulling on a handle that makes an angle x with the horizontal. The
4 answers
1,468 views
The velocity of the transverse waves produced by an earthquake is 7.2 km/s, while that of the longitudinal waves is 4.2 km/s. A
4 answers
4,664 views
A constant net force of 406 N, up, is applied to a stone that weighs 33 N. The upward force is applied through a distance of 2.4
2 answers
520 views
A 4610 kg helicopter accelerated upwards at 2 m/s^2. What lift force is exerted by the air on the propellers?
3 answers
413 views
A 4610 kg helicopter accelerated upwards at 2 m/s^2. What lift force is exerted by the air on the propellers?
I was given this
3 answers
501 views
A constant net force of 406 N, up, is applied to a stone that weighs 33 N. The upward force is applied through a distance of 2.4
2 answers
495 views
I am working on an oral presentation on Dorothy Parker for my creative writing class. I am required to focus on her non-fiction
2 answers
622 views
What is the answer to 14m= cm
4 answers
496 views
waht are lapse
1 answer
380 views
dear Ms.Sue what do they mean when they say find the tiime lapse.
3 answers
509 views
here is the problem Ms.Sue 6:32,9:29.
3 answers
368 views
Ms.Sue the answer is 2:47.I'm sorry for taking so long.
2 answers
894 views
Is it 2:57
1 answer
338 views
In the Supreme Court case Worcester v. Georgia (1832), the Court declared that Georgia’s laws _____ within Cherokee territory.
2 answers
714 views
Believing they had no choice, most Native American leaders in the Southeast signed treaties giving up their lands in the 1820s
2 answers
528 views
Answers (25)
Wtf
My calculations are . . . precise.
the answer is 2.5 ft/s ask me for the solution!
d = Vo*T. Vo = 52km/h = 52,000m/3600s. = 14.44 m/s. d = 14.44 * 0.701 =
thanks, everyone who answered the question
47.6
PE going into the down side: mgH KE is translational, and rotational or mgH=1/2 m v^2 + 1/2 Imr^2*w^2 mgH=1/2 m v^2 + 1/2 (1/2)mr^2*w^2 but when rolling, w=v/r mgH=1/2 m v^2+1/4*mv^2 =3/4mv^2 On the second side, rolling doesn t happen, the shell just
PE going into the down side: mgH KE is translational, and rotational or mgH=1/2 m v^2 + 1/2 Imr^2*w^2 mgH=1/2 m v^2 + 1/2 (1/2)mr^2*w^2 but when rolling, w=v/r mgH=1/2 m v^2+1/4*mv^2 =3/4mv^2 On the second side, rolling doesn t happen, the shell just
why are you guys talking about me
x=3 and y=2
1.C 2.C 3.D 4.A 5.C
I don't frickin know that's why im here to scheme answers not to give
You're in Mr. Moyer's Bio 205 class at WWU? If you check out page 317 of our book it really helps! "The bulk of the human genome is made of non-coding and repetitive nucleotide sequences" or junk. Hope that helps! Good luck tomorrow :)
Ms.Sue the answer is 2:47.And i'm sorry for taking so long.
I believe the units for latent heat are kJ/kg. so should ur answer be in kJ/(kg*km^2)? I don't understand the rest of the problem though.
y-5>-14 add 5 both sides y-5+5 > -14 + 5 y > -9 set of values is y greater than -9
Substitute y = 0 for x -intercept and solve for y
D = 685.44 km Thanks a lot!!
Thanks for your help.
A) Momentum = (2.465)(65) = 160.222 kgm/s B) 160.222 kgm/s C) Force = 160.222/.050 = 3204.441 N D) 3204.441/[(65)(9.8)] = 5.031
The mine shaft is 122.6 m deep. How do I find time?
Yes, I am supposed to use 343 m/s so: (343)(1)(.5)+(343)(2)(.5)=514.5 m/s
The mine shaft is 122.6 m deep. How do I find time?
Thank you!!
Thank you!!
